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# 05_curve_fitting | |
## Problem 2 | |
Coefficient of Determination | |
- Part A: 0.9801 | |
- Part B: 0.9112 | |
- Part C: 0.9462 | |
- Part D: 0.9219 | |
Best Fit Lines | |
### Part A | |
- y = 0.375+0.98644x+0.84564/x | |
![Part A Best Fit Line](./figures/figure1.png) | |
### Part B | |
- y = 22.47-1.36x+0.28x^2 | |
![Part B Best Fit Line](./figures/figure2.png) | |
### Part C | |
- y = 4.0046e^(-1.5x)+2.9213e^(-0.3x)+1.5647e^(-0.05x) | |
![Part C Best Fit Line](./figures/figure3.png) | |
### Part D | |
- y = 0.99sin(t)+0.5sin(3t) | |
![Part D Best Fit Line](./figures/figure4.png) | |
## Problem 3 | |
### Part A | |
```matlab | |
darts = dlmread('compiled_data.csv',',',1,0); | |
x_darts =darts(:,2).*cosd(darts(:,3)); | |
y_darts =darts(:,2).*sind(darts(:,3)); | |
ur = darts(:,1); | |
i = 1; | |
for r = 0:32 | |
i_interest = find(ur==r); | |
mx_ur(i)= mean(x_darts(i_interest)); | |
my_ur(i)= mean(y_darts(i_interest)); | |
i = i +1; | |
end | |
accuracy = mx_ur + my_ur; | |
val = 0; %value trying to be closest to | |
abs_accuracy = abs(accuracy-val); %takes absolute value of accuracy vector | |
[~, index] = min(abs_accuracy) | |
closest_value = accuracy(index) | |
``` | |
The most accurate dart thrower was person 31, with a combined x and y average of 0.0044 cm away from zero. | |
### Part B | |
```matlab | |
darts = dlmread('compiled_data.csv',',',1,0); | |
x_darts =darts(:,2).*cosd(darts(:,3)); | |
y_darts =darts(:,2).*sind(darts(:,3)); | |
ur = darts(:,1); | |
i = 1; | |
for r = 0:32 | |
i_interest = find(ur==r); | |
stdx_ur(i)= std(x_darts(i_interest)); | |
stdy_ur(i)= std(y_darts(i_interest)); | |
i = i +1; | |
end | |
precision = stdx_ur + stdy_ur; | |
val = 0; %value trying to be closest to | |
abs_accuracy = abs(precision-val); %takes absolute value of accuracy vector | |
[~, index] = min(abs_accuracy) | |
closest_value = precision(index) | |
``` | |
The most precise dart thrower was person 32, with a combined x and y standard deviation of 3.407. | |
## Problem 4 | |
### Part A | |
```matlab | |
function [mean_buckle_load,std_buckle_load]=buckle_monte_carlo(E,r_mean,r_std,L_mean,L_std) | |
r= normrnd(r_mean,r_std,[100 1]); | |
L= normrnd(L_mean,L_std,[100 1]); | |
p_cr = (pi.^3.*E.*r.^4)./(16.*L.^2); | |
mean_buckle_load = mean(p_cr); | |
std_buckle_load = std(p_cr); | |
end | |
``` | |
Output: | |
- Mean_buckle_load = 160.81 N | |
- Std_buckle_load = 70.21 N | |
### Part B | |
```matlab | |
N=100; | |
r_mean=0.01; | |
r_std=.001; | |
p_cr = 160.81; %N - from part A | |
r=normrnd(r_mean,r_std,[N,1]); | |
L = ((pi^3*E.*r.^4)./(16*p_cr)).^0.5; | |
L_mean = mean(L) | |
``` | |
Output: | |
- Length (L) = 4.955 m | |
## Problem 5 | |
### Part A | |
```matlab | |
cd_out_linear = sphere_drag(300,'linear') = 0.1750 | |
cd_out_spline = sphere_drag(300,'spline') = 0.1809 | |
cd_out_pchip = sphere_drag(300,'pchip') = 0.1807 | |
``` | |
### Part B | |
![Drag Force vs. Velocity - 3 Interpolation Methods](./figures/figure5.png) | |
## Problem 6 | |
| Method | Value | Error | | |
| --- | --- | --- | | |
| Analytical | 8.375 | 0% | | |
| 1 Gauss Point | 8.229 | 1.74% | | |
| 2 Gauss Point | 8.375 | 0% | | |
| 3 Gauss Point | 8.375 | 0% | |