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Merge pull request #7 from rcc02007/master
added lecture 18
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{ | ||
"cells": [], | ||
"metadata": {}, | ||
"nbformat": 4, | ||
"nbformat_minor": 2 | ||
} |
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function yint = Newtint_bak(x,y,xx) | ||
% Newtint: Newton interpolating polynomial | ||
% yint = Newtint(x,y,xx): Uses an (n - 1)-order Newton | ||
% interpolating polynomial based on n data points (x, y) | ||
% to determine a value of the dependent variable (yint) | ||
% at a given value of the independent variable, xx. | ||
% input: | ||
% x = independent variable | ||
% y = dependent variable | ||
% xx = value of independent variable at which | ||
% interpolation is calculated | ||
% output: | ||
% yint = interpolated value of dependent variable | ||
|
||
% compute the finite divided differences in the form of a | ||
% difference table | ||
n = length(x); | ||
if length(y)~=n, error('x and y must be same length'); end | ||
b = zeros(n,n); | ||
% assign dependent variables to the first column of b. | ||
b(:,1) = y(:); % the (:) ensures that y is a column vector. | ||
for j = 2:n | ||
for i = 1:n-j+1 | ||
b(i,j) = (b(i+1,j-1)-b(i,j-1))/(x(i+j-1)-x(i)); | ||
end | ||
end | ||
% use the finite divided differences to interpolate | ||
xt = 1; | ||
yint = b(1,1); | ||
for j = 1:n-1 | ||
xt = xt*(xx-x(j)); | ||
yint = yint+b(1,j+1)*xt; | ||
end |
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Flight#,Temp,O-Ring Problem | ||
1,53,1 | ||
2,57,1 | ||
3,58,1 | ||
4,63,1 | ||
5,66,0 | ||
6,66.8,0 | ||
7,67,0 | ||
8,67.2,0 | ||
9,68,0 | ||
10,69,0 | ||
11,69.8,1 | ||
12,69.8,0 | ||
13,70.2,1 | ||
14,70.2,0 | ||
15,72,0 | ||
16,73,0 | ||
17,75,0 | ||
18,75,1 | ||
19,75.8,0 | ||
20,76.2,0 | ||
21,78,0 | ||
22,79,0 | ||
23,81,0 |
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