initial repo commit

README.md

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+# Convert parallipiped dimesions to equivalent axisymmetric cylinder dimensions
+
+## For a given w x t x L block
+
+## Return the equivalent r x h cylinder
+
+## maintaining surface area and volume
+
+Running the code (2 options):
+
+1. open a terminal and type:
+
+  $ `python solve_cylinder_rt 1 2 3`
+
+  returns
+
+  `A 1.00 x 2.00 x 3.00 parallelipiped
+  has the same surface area and volume as a cylinder
+  that is r=0.6104 and t=5.1257`
+
+2. In a jupyter notebook, 
+
+  a. `import solve_cylinder_rt as sc`
+
+  b. `sc.solve_cylinder(1,2,3)`
+
+  `output: A 1.00 x 2.00 x 3.00 parallelipiped
+          has the same surface area and volume as a cylinder
+          that is r=0.6104 and t=5.1257`
+
+

solve_cylinder_rt.py

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+#!/opt/miniconda3/bin/python
+import numpy as np
+from scipy.optimize import fsolve
+import sys
+
+def parapiped(w,h,L):
+  A=2*(w*h+w*L+h*L)
+  V=w*h*L
+  return np.array([A,V])
+def cylinder(r,t):
+  A=2*np.pi*r*(r+t)
+  V=np.pi*r**2*t
+  return np.array([A,V])
+
+def matchAV(dim_cyl,dims):
+  r,t=dim_cyl
+  w,h,L=dims
+  AVp=parapiped(w,h,L)
+  AVc=cylinder(r,t)
+  return AVp-AVc
+
+def return_hr(w,h,L):
+  r,t=fsolve(matchAV,[1,2],args=[w,h,L])
+  print('A %1.2f x %1.2f x %1.2f parallelipiped'%(w,h,L) )
+  print('has the same surface area and volume as a cylinder')
+  print('that is r=%1.4f and t=%1.4f'%(r,t))
+
+
+if __name__=='__main__':
+  if len(sys.argv)<=3:
+    print('error, please enter w-by-t-by-L dimensions of parallelipiped as w t L')
+  else:
+    print(sys.argv)
+    w=float(sys.argv[1])
+    h=float(sys.argv[2])
+    L=float(sys.argv[3])
+    r,t=fsolve(matchAV,[1,2],args=[w,h,L])
+    print('A %1.2f x %1.2f x %1.2f parallelipiped'%(w,h,L) )
+    print('has the same surface area and volume as a cylinder')
+    print('that is r=%1.4f and t=%1.4f'%(r,t))
+