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# linear_algebra
3.
size of A | norm error
3 |
4 |
5. Solve spring mass system:
M = (1 0 0
0 2 0
0 0 4)
K = (k1+k2 -k2 0
-k2 k2+k3 -k3
0 -k3 k3+k4)
K = ( 30 -20 0
-20 40 -20
0 -20 30 )
Mx'' + Kx = 0
1*x1''+ 30*x1 - 20*x2 = 0
2*x2''- 20*x1 + 40*x2 - 20*x3 = 0
4*x3''- 20*x2 + 30*x3 = 0
k~ = ( 30 -14.2 0
-14.2 20.16 -7.1
0 -7.1 7.5 )
(k~ - (eigenvalue)I)*v = 0
det(k~ - (eigenvalue)I) = 0
eigenvalue = E
(30-E -14.2 0
-14.2 20.16-E -7.1 = 0
0 -7.1 7.5-E)
(30-E)(((20.16-E)*(7.5-E)) + 7.1(-7.1)) + 14.2(-14.2*(7.5-E))
(30-E)(100.79 + 12.66E + E^2) + -1512.3 - 201.64E
3023.7 + 379.8E + 30E^2 - 100.79E - 12.66E^2 -E^3 - 1512.3 - 201.64E
1511.4 + 77.37E + 17.34E^2 -E^3 = 0
E1 = 23.4
wn1 = 4.837m/s
6.
# of segments | largest | smallest | # of eigenvalues
5
6
10