README.md

# 06_initial_value_ode
# Problem 2
## Part A
The analytical solution to y' = -y is y = e^-t

## Part B

```
dt=[0.5 .1 .001];
figure();
hold on
     x=[0:dt(2):3]';
     y_n=zeros(size(x));
    y_n(1)=1;
for i=2:length(x)
    dy=prob2_ode(x,y_n(i-1));
    y_n(i)=y_n(i-1)+ dt(2)*dy;
end  
plot(x,exp(-x),x,y_n)
legend('Analytical','Euler','Location','Northeast')
```
![](assets/README-be88b588.png)

## Part C

```
function y=Prob2ptC(ode,dt,y0,tlimits)
maxit=100;
t=[tlimits(1):dt:tlimits(2)];
y=zeros(length(t),1);
y(1)=y0;
    for i=2:length(t)
        dy=ode(t(i-1),y(i-1));
        y(i)=y(i-1)+dt*dy;
        dyc=(dy+ode(t(i),y(i)))/2;
        y(i)=y(i-1)+dt*dyc;
        nits=1;

        while(1)
            nits=nits+1;
            yold=y(i);
            dyc=(dy+ode(t(i),y(i)))/2;
            y(i)=y(i-1)+dt*dyc;
            ea=abs(yold-y(i))/y(i)*100;
            if ea<.0001|nits>maxit;break;end;
        end;
    end
end
```
![](assets/README-8b7eb1c9.png)

# Problem 3
## Part A
The analytical solution is y = cos(3t)

## Part B
```
dt=[.1 .001];
figure();
hold on
x=[0:dt(2):3]';
y_n=zeros(length(x),2);
y_n(1,:)=[1,0];
for i=2:length(x)
        dy=prob3_ode(x,y_n(i-1,:));
        y_n(i,:)=y_n(i-1,:)+ dt(2)*dy;
end
plot(x,cos(3*x),x,y_n(:,1));
```
![](assets/README-bec1ab77.png)

## Part C
```
function y = prob3ptC(prob3_ode, dt, y0,tlimits)
    t = [tlimits(1):dt:tlimits(2)];
    y = zeros(length(t),length(y0));
    y(1,:) = y0;
    for i = 2:length(t)
        dy = prob3_ode(t(i-1),y(i-1,:));
        y(i,:) = y(i-1,:)+dt*dy;
        dyc = (dy + prob3_ode(t(i),y(i,:)))/2;
        y(i,:) = y(i-1,:)+dt*dyc;
        n = 1;
        while (1)
            n = n+1;
            yold = y(i,:);
            dyc = (dy+prob3_ode(t(i),y(i,:)))/2;
            y(i,:) = y(i-1,:)+dt*dyc;
            ea = abs(y(i,:)- yold)./y(i,:)*100;
            if max(ea) < 0.0001 || n>100; break, end
        end
    end
end
```
![](assets/README-fcbec9a1.png)

# Problem 4
## Part A
The analytical solution to v'=g-cd/m v*v is

## Part B
```
cd = 0.25;
m = 60;
g = 9.81;
dt = 0.1;
t = [0:dt:12]';
x = zeros(length(t),2);
x(1,:) = [1000, 0];
for i = 2:length(t)
    dx = prob4_ode(t,x(i-1,:));
    x(i,:) = x(i-1,:)+dt*dx;
end
```

## Part C
```
function x = prob4ptC(prob4_ode, dt, x0,tlimits)
    t = [tlimits(1):dt:tlimits(2)];
    x = zeros(length(t),length(x0));
    x(1,:) = x0;
    for i = 2:length(t)
        dx = prob4_ode(t(i-1),x(i-1,:));
        x(i,:) = x(i-1,:)+dt*dx;
        dxc = (dx + prob4_ode(t(i),x(i,:)))/2;
        x(i,:) = x(i-1,:)+dt*dxc;
        n = 1;
        while (1)
            n = n+1;
            yold = x(i,:);
            dxc = (dx+prob4_ode(t(i),x(i,:)))/2;
            x(i,:) = x(i-1,:)+dt*dxc;
            ea = abs(x(i,:)- yold)./x(i,:)*100;
            if max(ea) < 0.0001 || n>100; break, end
        end
    end
end
```
![](assets/README-ac6c7a25.png)

# Problem 5
![](assets/README-f6577255.png)