README.md

06_initial_value_ode

Problem 2

Part A

The analytical solution to y' = -y is y = e^-t

Part B

dt=[0.5 .1 .001];
figure();
hold on
     x=[0:dt(2):3]';
     y_n=zeros(size(x));
    y_n(1)=1;
for i=2:length(x)
    dy=prob2_ode(x,y_n(i-1));
    y_n(i)=y_n(i-1)+ dt(2)*dy;
end  
plot(x,exp(-x),'k-',x,y_n,'o');