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HW4/README.md

@@ 11,17 +11,17 @@ heading `# Homework #4` in your `README.md` file 





![Collarmass on an inclined rod](collar_mass.png) 





The spring is unstretched when $x_{C}=0.5$. The potential energy due to gravity is: 


The spring is unstretched when x_C=0.5 m. The potential energy due to gravity is: 





$PE_{g}=m x_{C}g\sin\theta$ 


PE_g=m x_C*g*sin(theta) 





where m=0.5 kg, and g is the acceleration due to gravity, 





and the potential energy due to the spring is: 





$PE_{s}=1/2K (\Delta L)^{2}$ 


PE_s=1/2*K *(DL)^2$ 





where $\Delta L = 0.5  \sqrt{0.5^{2}+(0.5x_{C})^{2}}$ 


where DL = 0.5  sqrt(0.5^2+(0.5x_C)^2) 





b. Use the `goldmin.m` function to solve for the minimum potential energy at xc when 


theta=0. *create an anonymous function with `@(x) collar_potential_energy(x,theta)` in 


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