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September 15, 2017 13:41
September 15, 2017 13:44
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October 5, 2017 20:31
September 10, 2017 21:09

homework_1

Answer to homework question

I hope to learn more about Matlab and how to make it useful for me as an engineer

I worked on trying to get this to be the matlab code and followed all the directions on how to make it appear as matlab code on github but it would never change to appear as the matlab code.

Problem 3

'''matlab A_66=zeros(6,6); for i=1:6 for j=1:6 A_66(i,j)=i*j; end end fprintf('mean of A_66 =%1.2f\nstdev of A_66 =%1.2f\n',mean(A_66(:)),std(A_66(:))) '''

Outputs: mean of A_66 =12.25 stdev of A_66 =9.07

Problem 4

'''matlab data=dlmread('US_energy_by_sector.csv',',',2,0); h=figure(); plot(data(:,1),data(:,3),data(:,1),data(:,9)) legend('Residential','Transportation','Location','Northwest') xlabel('years') ylabel('trillions of Btus') saveas(h,'problem4.png') ''' US energy use per year from 1949-2016

Problem 5

'''matlab function [v_analytical,v_terminal,t]=freefall(h,timespan) % help file for freefall.m % N is number of timesteps between 0 and 12 sec % v_an... % t=linspace(0,12,N)'; t=(0:h:timespan)'; c=0.25; m=60; g=9.81; v_terminal=sqrt(m*g/c);

v_analytical = v_terminal*tanh(g*t/v_terminal);
v_numerical=zeros(length(t),1);
delta_time =diff(t);
for i=1:length(t)-1
v_numerical(i+1)=v_numerical(i)+(g-c/m*v_numerical(i)^2)*delta_time(i);
end
% Print values near 0,2,4,6,8,10,12 seconds
f=figure();
indices = round(linspace(1,length(t),7));
fprintf('time (s)|vel analytical (m/s)|vel numerical (m/s)\n')
fprintf('-----------------------------------------------\n')
M=[t(indices),v_analytical(indices),v_numerical(indices)];
fprintf('%7.1f | %18.2f | %15.2f\n',M(:,1:3)');
plot(t,v_analytical,'-',t,v_numerical,'o-')
saveas(f,'Problem5.png')

end ''' freefall plot

Freefall comparison '''matlab c=0.25; m=60; g=9.81; v_terminal=sqrt(mg/c); h1 = 0.1; timespan = 30 ; t1=(0:h1:timespan)'; v_analytical1 = v_terminaltanh(gt1/v_terminal); h2 = 1 ; t2=(0:h2:timespan)'; v_analytical2 = v_terminaltanh(gt2/v_terminal); h3 = 5 ; t3=(0:h3:timespan)'; v_analytical3 = v_terminaltanh(g*t3/v_terminal); f = figure() plot(t1, v_analytical1,'-', t2, v_analytical2,'o-', t3,v_analytical3,'--') saveas(f, 'problem5.png') ''' freefall comparison

Problem 6

'''matlab function [vx,vy,vz] = my_velocity(x,y,z,t) % Help documentation of "my_velocity" % This function computes the velocity in the x- and y-directions given % three vectors of position in x- and y-directions as a function of time % x = x-position % y = y-position % t = time % output % vx = velocity in x-direction % vy = velocity in y-direction

vx=zeros(length(t),1);
vy=zeros(length(t),1);
vz=zeros(length(t),1);

vx(1:end-1) = diff(x)./diff(t); % calculate vx as delta x/delta t
vy(1:end-1) = diff(y)./diff(t); % calculate vy as delta y/delta t
vz(1:end-1) = diff(z)./diff(t);

vx(end) = vx(end-1);
vy(end) = vy(end-1);
vz(end) = vz(end-1);

end

function [ax,ay,az]=my_acceleration(x,y,z,t) % Help documentation of "my_acceleration" % This function computes the acceleration in the x- and y-directions given % three vectors of position in x- and y-directions as a function of time % x = x-position % y = y-position % t = time % output % ax = acceleration in x-direction % ay = acceleration in y-direction

function v=diff_match_dims(x,t)
  v=zeros(length(t),1);
  v(1:end-1)=diff(x)./diff(t);
  v(end)=v(end-1);
end

[vx,vy,vz]=my_velocity(x,y,,zt);

ax = diff_match_dims(vx,t);
ay = diff_match_dims(vy,t);
az = diff_match_dims(vz,t);

end '''

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